Write a quadratic equation in standard form (with integer coefficients) that has roots: 2 and - 5?

y = x^2 + 3x-10

Step-by-step explanation:

If we know the roots of a quadratic function, we know that

y = (x - a) (x-b) where a and b are the roots

y = (x-2) (x--5)

y = (x-2) (x+5)

We need to foil this out to get this in standard form of ax^2 + bx+c

FOIL (x-2) (x+5)

First x*x: x^2

outer : 5*x = 5x

inner: - 2x = - 2x

last : - 2*5 = - 10

Add them up

x^2 + 5x-2x-10

x^2 + 3x-10