Rearrange the following steps in the correct order to locate the last occurrence of the smallest element in a finite list of integers, where the integers in the list are not necessarily distinct.

a. return location

b. min ≔a1 and location ≔1

c. min ≔ai and location≔i

d. procedure last smallest (a1, a2, ..., an: integers)

e. If min > = ai then

The rearranged steps is as follows:

d. procedure last smallest (a1, a2, ..., an: integers)

b. min ≔a1 and location ≔1

e. If min > = ai then

c. min ≔ai and location≔i

a. return location

Step-by-step explanation:

The proper steps to perform the task in the question above is dbeca

Here, the procedure (or function) was defined along with necessary parameters

d. procedure last smallest (a1, a2, ..., an: integers)

The smallest number is initialized to the first number on the list and its location is initialized to 1

b. min ≔a1 and location ≔1

The next line is an if conditional statement that checks if the current smallest number is greater than a particular number

e. If min > = ai then

If the above condition is true, the smallest value is assigned to variable min; it's location is also assigned to variable location

c. min ≔ai and location≔i

The last step returns the location of the smallest number

a. return location