One number is 6 less than 3 times another number and their sum is 62. find the numbers

y = 6 - 3x

x + y = 62

Since we already know the value of y, we can use substitution to find the value of x.

x + 6 - 3x = 62

Subtract 6 from both sides.

x - 3x = 56

Combine like terms.

-2x = 56

Divide both sides by - 2

x = - 28

Now that we know the value of x, we can solve for the value of y.

x + y = 62

-28 + y = 62

Add 28 to both sides

y = 90

The value of y is 90, and the value of x is - 28 (this is your answer)

To make sure that these values are correct, we can plug them into the original equations.

y = 6 - 3x

x + y = 62

90 = 6 - 3 (-28)

90 = 90 √ this is correct

-28 + 90 = 62

62 = 62 √ this is also correct