Ask Question
20 October, 07:57

A jar containing only nickels and dimes contains a total of 60 coins. The value of all the coins in the jar is $4.45. Solve by elimination to find the number of nickels and dimes that are in the jar.

+5
Answers (1)
  1. 20 October, 08:36
    0
    Answer: 31 nickels and 29 dimes

    Step-by-step explanation:

    Nickels (.05) : x

    Dimes (.10) : y

    Value:.05x +.10y = 4.45 → - 20 (.05x +.10y = 4.45) → - x - 2y = - 89

    Quantity: x + y = 60 → 1 (x + y = 60) → x + y = 60

    -y = - 29

    y = 29

    Next, substitute "29" for "y" into either equation and solve for "x":

    x + y = 60

    x + 29 = 60

    x = 31
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A jar containing only nickels and dimes contains a total of 60 coins. The value of all the coins in the jar is $4.45. Solve by elimination ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers