Find the inverse of the logarithmic function y = log₂ (x + 7)

y = x2 - 7

y = x2 + 7

y = 2x2 + 7

y = 2x - 7

y = 2x + 7

Question

Mathematics

Midge

29 September, 12:20

Find the inverse of the logarithmic function y = log₂ (x + 7)

y = x2 - 7

y = x2 + 7

y = 2x2 + 7

y = 2x - 7

y = 2x + 7

+1

Answers (2)

Know the Answer?

Mariana Benitez · Answer 1

y=2x-7 answered off of a graphing calculator

Trinity Walton · Answer 2

1. Interchange x and y: x = log₂ (y + 7)

2. Solve this resulting equatino for y:

x x

2 = y + 7 = > y = 2 - 7

3. Replace "y" with

-1 - 1 x

f (x) : f (x) = 2 - 7 This is the desired inverse.

Find the inverse of the logarithmic function y = log₂ (x + 7)y = x2 - 7y = x2 + 7y = 2x2 + 7y = 2x - 7y = 2x + 7

Find the inverse of the logarithmic function y = log₂ (x + 7)

y = x2 - 7

y = x2 + 7

y = 2x2 + 7

y = 2x - 7

y = 2x + 7