Evaluate the summation of 3 n plus 2, from n equals 1 to 14 ...

3n + 2 when n = 1 = 3 + 2 = 5

when n = 2 we have the 2nd term which is 3 (2) + 2 = 8

for n = 3 we have 3rd term = 11 and so on

This is an arithmetic series with first term a1 = 5 and common difference = 3

so Sn = (n/2) (2a1 + (n - 1) d))

there fore Sum of 14 terms = (14/2) (2*5 + 13*3)

= 7 * 49 = 343 answer