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11 August, 18:40

The quadratic x^2+7x+20$ has the same roots as the quadratic Ax^2+Bx+1 What is A+B?

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  1. 11 August, 22:30
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    If f (x) = x^2+7x+20 has the same roots as g (x) = Ax^2+Bx+1, then

    one must be a multiple of the other.

    By comparison of the constant terms, we know that 20g (x) = f (x), or

    g (x) = (1/20) f (x)

    = (1/20) (x^2+7x+20)

    = (1/20) x^2 + (7/20) x + 20/20

    = (1/20) x^2 + (7/20) x + 1

    Therefore A = (1/20), B = (7/20), and A+B = (1+7) / 20=8/20=2/5
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