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16 November, 10:57

The equation d = 16t^2 gives the distance d in feet that a golf ball falls in t seconds. How many seconds will it take a golf ball to drop to the ground from a height of 4 feet? 64 feet?

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  1. 16 November, 14:40
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    Answer: 0.5 seconds for 4 ft and 2 seconds for 64 ft

    d=16t^2

    4=16t^2

    /16 / 16

    t^2=1/4

    t=1/2

    0.5 seconds for 4 ft

    64 = 16t^2

    /16 / 16

    4=x^2

    x=2

    2 seconds for 64 ft
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