Right triangle ABC with right angle C has a hypotenuse of length 10. If AB = 2 CB, what is the length side AC

In right angle ΔABC, if ∠C is the right angle, then the hypotenuse is AB.

Given that the hypotenuse is 10, therefore AB = 10

AB = 2CB

10 = 2CB

CB = 10 : 2 = 5

Pythagoras' theorem: a² + b² = c²

5² + AC² = 10²

AC² = 10² - 5²

AC² = 75

AC = √75

AC = 5√3

Answer: AC = 5√3

AB = 10

AB = 2CB

10 = 2CB

CB = 5

10^2 - 5^2 = AC^2

75 = AC^2

AC = sqrt (75)

AC = 5sqrt (3)