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20 March, 00:26

The ages of alligators in a swamp are normally distributed, with a mean of 50 years and a standard deviation of 4. Approximately what percentage of the alligators are between 45 and 55 years old?

78.87%

10.56%

89.44%

67.76%

+5
Answers (2)
  1. 20 March, 03:14
    0
    The percentage is 78.88%

    So, Option A is correct.

    Step-by-step explanation:

    Mean = 50

    Standard Deviation = 4

    Percentage of the alligators are between 45 and 55 years old = ?

    We need to find z-score when x = 45 and when x = 55

    For x = 45

    z-score = x - Mean/Standard Deviation

    z-score = 45-50/4

    z-score = - 1.25

    P (z=-1.25) can be found by using z-score table

    P (z = - 1.25) = 0.1056

    For x = 55

    z-score = x - Mean/Standard Deviation

    z-score = 55-50/4

    z-score = 1.25

    P (z = 1.25) can be found by using z-score table

    P (z = 1.25) = 0.8944

    So, area between 45 and 55 is area between z = - 1.25 and z = 1.25

    Subtracting the values of P (z = - 1.25) from P (z = 1.25)

    0.8944 - 0.1056 = 0.7888

    So, the percentage is 78.88%

    So, Option A is correct.
  2. 20 March, 03:57
    0
    A

    Step-by-step explanation:

    i just took it and made a 90
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