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10 November, 09:25

The exponential distribution is frequently applied to the waiting times between successes in a poisson process. if the number of calls received per hour by a telephone answering service is a poisson random variable with parameter Î" = 6, we know that the time, in hours, between successive calls has an exponential distribution with parameter β = 1/6. what is the probability of waiting more than 15 minutes between any two successive calls?

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  1. 10 November, 10:20
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    P (x>15) = 0.9656

    Step-by-step explanation:

    No. of calls received is a poisson random variable with parameter = 6

    mean = 6

    And the waiting time between the phone calls received is exponentially distributed with parameter m = 1/6.

    We need to find the waiting time more than 15 minutes.

    1hour = 60 minutes

    15 minutes = 0.214 hours.

    P (x>x) = e^{-mx)

    P (x>0.214) = e^{-0.214/6}

    = 0.9656
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