Which of the following explains why the given radical is not in simpliest form ^3√162

27 is a factor of 162. C on edge

This is a cube root, so we look for factors of 162 which are perfect cubes.

Find the prime factors of 162:-

162 = 2 * 3 * 3 * 3 * 3

27 = 3^3 is a perfect cube

162 = 6 * 27

so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3

so the simplest form is 3 ^3√6