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19 February, 20:44

Two functions are shown below.

f (x) = 1/2 • 2^x

g (x) = 5x + 2

What is the largest integer value of x such that f (x) ≤ g (x) ?

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  1. 19 February, 22:52
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    x = 6

    Step-by-step explanation:

    As the function f (x) is an exponencial function, it will grow faster than g (x), that is a linear function.

    For small values of x, we have that f (x) < g (x). For example:

    f (1) = 1/2 * 2 = 1

    g (1) = 5*1 + 2 = 7

    f (2) = 1/2 * 4 = 2

    g (2) = 5*2 + 4 = 14

    So we just need to check some integer values and see when f (x) will be bigger than g (x). It will not be a big value, as the exponencial function grows very fast.

    For x = 5, we have:

    f (5) = 1/2 * 32 = 16

    g (5) = 5*5 + 4 = 29

    For x = 6, we have:

    f (6) = 1/2 * 64 = 32

    g (6) = 5*6 + 4 = 34

    For x = 7, we have:

    f (7) = 1/2 * 128 = 64

    g (7) = 5*7 + 4 = 39

    So the largest integer value of x for f (x) ≤ g (x) is x = 6.

    Another way to solve this is by plotting both equations, and then checking where they cross, that is, where f (x) = g (x).
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