Ask Question
23 June, 17:58

Find the center of a circle with the equation: x^2 + y^2 - 2y - 8x - 19 = 0

+2
Answers (1)
  1. 23 June, 18:40
    0
    (4, 1)

    Step-by-step explanation:

    x^2 + y^2 - 2y - 8x - 19 = 0

    We rearrange the terms and complete the square twice.

    x^2 - 8x + y^2 - 2y = 19

    x^2 - 8x + 16 + y^2 - 2y + 1 = 19 + 16 + 1

    (x - 4) ^2 + (y - 1) ^2 = 6^2

    The center is (4, 1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find the center of a circle with the equation: x^2 + y^2 - 2y - 8x - 19 = 0 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers