How do you factor 18x^2-27*+4? can you demonstrate it?

Well to factor a trinomial (Which is in the form ax^2 + bx + c) You would have to bring the A over to c so you can get x^2 alone. (If their isn't a gcf) You could also try to find what multiplys ac to add to b. but since that is not possible you would rewrite it x^2 - 27x + 72 (by multiplying the a to c) The you would rework it as normal (whatever two numbers multiply to 72 and add to - 27. Which would be (x-3) (x-24). Then you would divide by the original A (x-3/18) (x-24/18). Then you would simplify that. (x-6) (x-4/3) and you would take any extra denominators and bring it to the front of the x. Making it (x-6) (3x-4)