Ask Question
10 July, 14:12

Find the center, vertices, and foci for the ellipse 25x^2+64y^2=1600

+1
Answers (2)
  1. 10 July, 14:39
    0
    Step-by-step explanation:

    Answer:

    Data

    Equation 25x² + 64y² = 1600

    Process

    1. - Divide all the equation by 1600

    25x²/1600 + 64y² / 1600 = 1600/1600

    -Simplify

    x²/64 + y² / 25 = 1

    2. - Equation of a horizontal ellipse

    3. - Find a, b and c

    a² = 64 a = 8

    b² = 25 b = 5

    -Calculate c with the Pythagorean theorem

    a² = b² + c²

    -Solve for c

    c² = a² - b²

    -Substitution

    c² = 8² - 5²

    -Simplification

    c² = 64 - 25

    c² = 39

    -Result

    c = √13

    4. - Find the center

    C = (0, 0)

    5. - Find the vertices

    V1 = (-8, 0) V2 = (8, 0)

    6. - Find the foci

    F1 = (-√13, 0) F2 = (√13, 0)
  2. 10 July, 15:49
    0
    Answer: A

    Step-by-step explanation: Center (0,0)

    Vertices (+/-8,0)

    Foci (+/-6.2,0)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find the center, vertices, and foci for the ellipse 25x^2+64y^2=1600 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers