Write the equation in vertex form.

f (x) = x^2 + 10x - 5

y = (x + 5) ² - 30 where vertex for the parabola is (-5,-30).

Step-by-step explanation:

We have given a function:

f (x) = x² + 10x - 5

We have to find the vertex form given form.

Let y = f (x)

y = x² + 10x - 5

The general vertex form:

y = a (x-h) ²+h

First, we have to complete the square we have,

y = x² + 10x - 5

y = x² + 2 (x) (5) - 5 + (5) ² - (5) ²

y = (x + 5) ²-5-25

y = (x + 5) ² - 30

y = (x + 5) ² - 30 where vertex for the parabola is (-5,-30).