The area of a playground is 204 yd^2 The width of the playground is 5 yd longer than its length. Find the length and width of the playground.

length = 17 yd, width = 12 yd

12

Step-by-step explanation:

Assuming that the shape of the playground is rectangular, we know that the area of a rectangle is length x width.

Let the length = x

width = x + 5

x (x + 5) = 204

x² + 5x = 204

x² + 5x - 204 = 0

(x + 17) (x - 12) = 0

x = - 17 and x = 12

However, since x represents the length of the playground, length cannot be negative. The only value possible is x = 12.

Therefore, the playground has a length of 12 yd and a width of 12 + 5 = 17 yd.