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29 August, 03:31

If f (1) = 1 and f (n) = (n-2) ^2 + n then find the value of f (3)

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  1. 29 August, 05:48
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    f (3) = 4

    Step-by-step explanation:

    f (n) = (n-2) ^2 + n

    We want to find f (3)

    Put in n=3

    f (3) = (3-2) ^2 + 3

    f (3) = 1^2 + 3

    f (3) = 1+3

    f (3) = 4
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