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11 June, 13:13

What's the equation of the line that passes through (-4,3) and is perpendicular to the line y=7/5x-3/5

A) 5x+7y=1

B) 7x+5y=-13

C) 7x+5y=-1

D) 3x+5y=7

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Answers (1)
  1. 11 June, 14:50
    0
    Two lines perpendicular to each other having slopes m1 and m2 are related as:

    m1 * m2=-1 ... (1)

    First we find slope m1 of the line y=7/5x-3/5

    comparing this equation with slope intercept form y=mx+b,

    slope m1=7/5

    NOw using rule (1) here to get value of m2

    7/5 * m2 = -1

    m2 = -5/7 ... (2)

    Now the line passes through (-4,3) and has slope m2 = -5/7

    we use slope intercept form to get the value of y intercept

    y=mx+b

    3 = (-5/7) (-4) + b

    3=2.86 + b

    b=0.14

    At last we plug the value of b and m in slope intercept form to get the final equation as:

    y = (-5/7) x + 0.14
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