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25 December, 12:24

What are the lengths of the legs of a triangle in which one acute angle measures 19 degrees and the hypotenuse is 15 units long?

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  1. 25 December, 13:36
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    Sin (19°) = side a / 15

    side a = 15 * sin (19°)

    side a = 15 * 0.32557

    side a = 4.88355

    side b^2 = 15^2 - 4.88355^2

    side b^2 = 225 - 23.8490606025

    side b^2 = 201.15

    side b = 14.18
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