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10 July, 16:50

A pumpkin is launched directly upwards at 72 feet per second from a platform 12 feet high. The pumpkin's height, h, at time t seconds can be represented by the equation h (t) = - 16t^2+72t+12. Find the maximum height of the pumpkin and the time it takes to reach it.

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  1. 10 July, 18:56
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    93 feet

    Step-by-step explanation:

    Let us first find the time it takes to reach the maximum height. We can do this by differentiating the height function to get velocity:

    dh (t) / dt = v (t) = - 32t + 72

    The maximum height will occur when the velocity becomes 0. Therefore, the time it takes to reach maximum height is:

    0 = - 32t + 72

    32t = 72

    t = 72/32 = 2.25 seconds

    Therefore, the maximum height of the pumpkin is:

    h (2.25) = - 16 (2.25) ^2 + 72 (2.25) + 12

    h (2.25) = - 81 + 162 + 12

    h = 93 feet
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