Find the 6th term of the geometric sequence, given the first term and common ratio a1 = 5 and r=3/2

Answer

37.96875

Explanation

In geometric sequence we use the formula below to find the nth of a sequence.

Tn = ar⁽ⁿ⁻¹⁾

Where a ⇒ first term

n ⇒ the term we are looking for

T₆ = 5 * (3/2) ⁶⁻¹

= 5 * (3/2) ⁵

= 5 * 243/32

= 1215/32

= 37 31/32

= 37.96875