wo numbers are randomly selected on a number line numbered from 1 to 9. Match each scenario to its probability. the probability that both numbers are greater than 6 if the same number can be chosen twice the probability that both numbers are less than 7 if the same number can be chosen twice the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice the probability that both numbers are even numbers if the same numbers cannot be chosen twice arrowRight arrowRight arrowRight arrowRight

the probability that both numbers

are greater than 6 if the same

number can be chosen twice = 1/9

the probability that both numbers

are less than 7 if the same

number can be chosen twice = 4/9

the probability that both numbers

are odd numbers less than 6 if the

same numbers cannot be chosen

twice = 1/12

the probability that both numbers

are even numbers if the same

numbers cannot be chosen twice = 1/6

In all cases, the events are independent. That's why we have to multiply the results.

Probability that both numbers are greater than 6 if the same number can be chosen twice.

P = 3 / 9 * 3 / 9 = 1/9 because possible outcomes are the pairs (7,8), (7,9) and (8,9).

Probability that both numbers are less than 7 if the same number can be chosen twice

P = 6 / 9 * 6 / 9 = 4/9

Probability when both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice

P = 3/9 * 2/8 = 1/12, odd numbers less than 6 are 1, 3 and 5. If the same number cannot be chosen depending on these numbers, we'll end up with 2 in possible outcome for the 2nd pair of the probability.

Probability that both numbers are even numbers if the same numbers cannot be chosen twice is

P = 4/9 * 3/9 = 4/27. The same logic is possible in this case, as well