With a rate of change = 0.10 & an initial value = 10, how would you represent this as a linear equation?

y = 0.10x + 10, where m = 0.10 & b = 10

y = 10x + 0.10, where m = 10 & b = 0.10

Question

Mathematics

Areli

25 May, 02:36

With a rate of change = 0.10 & an initial value = 10, how would you represent this as a linear equation?

y = 0.10x + 10, where m = 0.10 & b = 10

y = 10x + 0.10, where m = 10 & b = 0.10

+2

Answers (2)

Know the Answer?

Marcel Gutierrez · Answer 1

y =.10x + 10

Step-by-step explanation:

If the equation is linear, we can write it in the form y=mx+b where m is the slope and b is the y intercept

The y intercept is where we start, or the initial value

The slope is also call the rate of change

y =.10x + 10

Ticklebutt · Answer 2

First one

Step-by-step explanation:

rate of change = 0.10

Means

The slope = 0.10

m = 0.10

An initial value = 10

Means

y-intercept = 10

b = 10

y = mx + b

y = 0.10x + 10

With a rate of change = 0.10 & an initial value = 10, how would you represent this as a linear equation?y = 0.10x + 10, where m = 0.10 & b = 10y = 10x + 0.10, where m = 10 & b = 0.10

With a rate of change = 0.10 & an initial value = 10, how would you represent this as a linear equation?

y = 0.10x + 10, where m = 0.10 & b = 10

y = 10x + 0.10, where m = 10 & b = 0.10