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16 October, 13:26

Which is the same solution a x2-16x+12 = 0

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  1. 16 October, 17:09
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    An equation which has the same solution as the given equation is:

    (x - 18) (x + 2) + 48 = 0 ...

    Step-by-step explanation:

    The given expression is:

    x2-16x+12

    Break the constant term:

    x^2-16x-36 + 48=0

    [x^2-16x-36] + 48=0

    Now break the middle term inside the brackets

    (x^2-18x+2x-36) + 48=0

    Take the common

    [x (x-18) + 2 (x-18) ]+48=0

    (x-18) (x+2) + 48=0

    Thus an equation which has the same solution as the given equation is:

    (x - 18) (x + 2) + 48 = 0 ...
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