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1 December, 20:54

There were 6,985 9th grade students in Seattle in 2017, and 3.2% of

these students could not finish the 9th grade. How many 9th students

who should not have failed in the 9th grade so that the failing percent

can be at 2%?

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Answers (1)
  1. 2 December, 00:19
    0
    Answer:83.82 so basically 84

    Step-by-step explanation:

    3.2% - 2% = 1.2%

    1.2% / 100 = 0.012

    0.012 x 6985 = 83.82
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