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3 November, 02:01

find three consecutive integers such that three times the third is 102 more than the sum of the first and second

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  1. 3 November, 02:14
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    97,98,99

    Step-by-step explanation:

    x-1 + x + x+1

    x-1+x + 102=3 (x+1)

    2x + 101 = 3x+3

    2x+98=3x

    x=98
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