Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.

Question

Mathematics

Trey Parrish

17 September, 14:05

Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.

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Answers (1)

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Gretchen Munoz · Answer 1

Hello,

Choice urn_1: 1/3

choice R: 5/8 = = >1/3*5/8=5/24

Choice urn_2: 1/3

Choice R: 3/4 = = > 1/3*3/4=1/4

Choice urn_3: 1/3

Choice R:4/6=2/3 = = > 1/3*2/3=2/9

Total: 5/24+1/4+2/9=15/72+18/72+16/72=49/72