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MathematicsMathematics
17 September, 14:05

Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.

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  1. 17 September, 16:05
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    Hello,

    Choice urn_1: 1/3

    choice R: 5/8 = = >1/3*5/8=5/24

    Choice urn_2: 1/3

    Choice R: 3/4 = = > 1/3*3/4=1/4

    Choice urn_3: 1/3

    Choice R:4/6=2/3 = = > 1/3*2/3=2/9

    Total: 5/24+1/4+2/9=15/72+18/72+16/72=49/72
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Home » Mathematics » Urn 1 contains 5 red balls and 3 black balls. Urn 2 contains 3 red balls and 1 black ball. Urn 3 contains 4 red balls and 2 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red.
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