Ask Question
2 May, 16:51

Plot the x-intercept (s), y-intercept, vertex, and axis of symmetry of the function.

h (x) = (x+1) ^2-4

+3
Answers (1)
  1. 2 May, 19:27
    0
    see explanation

    Step-by-step explanation:

    the equation of a parabola in vertex form is

    y = a (x - h) ² + k

    where (h, k) are the coordinates of the vertex and a is a multiplier

    h (x) = (x + 1) ² - 4 is in this form, hence

    vertex = ( - 1, - 4)

    the axis of symmetry passes through the vertex is vertical with equation

    y = - 1 ← axis of symmetry

    To find the y - intercept let x = 0 in the equation

    h (0) = (0 + 1) ² - 4 = 1 - 4 = - 3 ⇒ (0, - 3) ← y - intercept

    to find the x-intercepts let y = 0 in the equation, hence

    (x + 1) ² - 4 = 0 (add 4 to both sides)

    (x + 1) ² = 4 (take the square root of both sides)

    x + 1 = ± 2 (subtract 1 from both sides)

    x = - 1 ± 2 ⇒ x = - 1 - 2 = - 3, x = - 1 + 2 = 1, hence

    ( - 3, 0), (1, 0) ← x - intercepts
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Plot the x-intercept (s), y-intercept, vertex, and axis of symmetry of the function. h (x) = (x+1) ^2-4 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers