Find the direction angle of the vector b=.

74.7450

105.2550

164.7450

149.7420

The given vector is b = - 3i + 11j

b=

here, base = 3 (not - 3) (this gives an angle in first quadrant the same angle will foam in second quadrant from - ve x-axis) and perpendicular = 11

Now,

tan (θ') = perpendicular/base = 11/3

θ' = tan⁻¹ (11/3)

= 74.7448°

but we require the angle from positive x-axis so,

θ = 180-θ'

= 180-74.7448

= 105.255°

B is the correct answer.