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15 July, 16:57

Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third

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  1. 15 July, 19:00
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    3, 5, 7

    Step-by-step explanation:

    1st number: (2k+1)

    2nd number: (2k+3)

    3rd number: (2k+5), k∈Z

    3*[ (2k+1) + (2k+3) ] = 3 + 3 * (2k+5)

    3 * (4k+4) = 3+6k+15

    12k+12=18+6k

    6k=6

    k=1

    1st number: (2k+1) = 3

    2nd number: (2k+3) = 5

    3rd number: (2k+5) = 7
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