The length of a new rectangular playing field is 4 yards longer than triple the width. if the perimeter of the rectangular playing field is 408 yards, what are it's dimensions?

The length is 4 yards longer than 3width so L = 3W+4

perimeter equal 408 yards

perimeter equal 2L + 2W = 2 (3W+4) + 2W

408 = 6W + 8 + 2W

400=8W

W = 50

L = 3*50 + 4 = 154

L = 154

W = 50

P = 2L + 2W

408 = 2*50 + 2*154

408 = 100 + 308

408 = 408

hope that this is easy understandably