X^2+y^2-10x-16y+53=0

What is the center of the circle?

What is the radius of the circle?

Step-by-step explanation:

hello : Completing The Square

X²+y²-10x-16y+53=0 means : (x²-10x+25-25) + (y²-16y+16-16) + 53 = 0

(x²-10x+25) - 25) + (y²-16y+64) - 64+53 = 0

(x+5) ² + (y-8) ² - 25-64+53=0

(x+5) ² + (y-4) ² = 6² standard form

the center is (-5, 4) and the radius : 6