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3 November, 00:22

Which of the following could be values for a, b, and c so that (3x - 2) (2x-7) = ax^2 + bx+c?

A. A=6 B=25, C=14 B. A=6 B=-25, C=14

C. A=6 B=-24, C=-14 D. A=5, B=-25, C=-9

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Answers (2)
  1. 3 November, 01:39
    0
    B

    Step-by-step explanation:

    Expand the factors and compare coefficients of like terms

    (3x - 2) (2x - 7)

    = 6x² - 21x - 4x + 14

    = 6x² - 25x + 14

    Compare coefficients to ax² + bx + c

    ax² → 6x² ⇒ a = 6

    bx → - 25x ⇒ b = - 25

    14 → c ⇒ c = 14

    a = 6, b = - 25, c = 14 → B
  2. 3 November, 04:10
    0
    B. A=6 B=-25, C=14

    Step-by-step explanation:

    (3x - 2) (2x-7)

    Using FOIL

    = 6x^2 - 21x - 4x + 14

    = 6x^2 - 25x + 14

    So a = 6, b = - 25 and c = 14

    answer

    B. A=6 B=-25, C=14
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