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23 January, 05:06

Consider a test that has a normal distribution, a mean of 100, and a standard deviation of 14. how high of a score would a person need to be in the top 1%

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  1. 23 January, 06:02
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    A test has normal distribution with mean μ = 100 and standard deviation σ = 14

    Let X be the score obtained by person in test. Here we have to find test score x such that person would be in top 1%

    It means x is such that probability above x is 0.01 and below is 0.9

    So we will find z score such that area below z is 0.9

    In z score table there is no accurate probability value 0.9 so we take probability value close to 0.9 which is 0.8997 and corresponding z score is 1.28

    Now we will find x value from z=1.28

    x = (z * standard deviation) + mean

    x = (1.28 * 14) + 100

    x = 117.92 ~ 118

    The score value for a person to be in top 1% is 118.
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