What are the solutions of 3x^2+6x+6=0

x = - 1 + i, - 1 - i,

Step-by-step explanation:

3x^2 + 6x + 6 = 0

Divide through by 3:

3 (x^2 + 2x + 2) = 0

Using the quadratic formula

x = [-2 + / - √2^2 - 4*1*2) ] / 2

x = (-2 + / - √-4) / 2

x = (-2 + / - 2i) / 2

x = - 1 + i, - 1 - i,

x = - 1+i; - 1-i