Allen has four times as many cards as Bob, and Jane has twice as many cards as Allen. Together, Allen and Jane have 468 cards. How many cards do Allen, Jane, and Bob each have?

Question

Mathematics

Greta Meza

1 November, 21:48

Allen has four times as many cards as Bob, and Jane has twice as many cards as Allen. Together, Allen and Jane have 468 cards. How many cards do Allen, Jane, and Bob each have?

+4

Answers (1)

Know the Answer?

Jordan Pham · Answer 1

156

312 and

39

Step-by-step explanation:

Let Allen be A, Jane be J and Bob be B

Allen has 4 times as Bob

So

A = 4B

Jane has twice as Allen

So

J = 2A

Together, Allen and Jane has 468 cards

A + J = 468

Substitute 2A for J in the third equation.

We have

A + J = 468

A + 2A = 468

3A = 468

Divide both sides by 3

3A/3 = 468/3

A = 156

Recall

A = 4B

Therefore

156 = 4B

Divide both sides by 4

156/4 = 4B/4

39 = B

B = 39

Also,

J = 2A

J = 2 x 156

J = 312

Allen has 156 cards

Jane has 312 cards and

Bob has 39 cards