Ask Question
8 April, 00:06

Fully Factor 3x^2 - 16x + 20

A. (3x + 10) (x - 2)

B. None of the answers are correct

C. (3x - 10) (x - 2)

D. (3x² - 4) (x - 5)

+4
Answers (1)
  1. 8 April, 03:27
    0
    C. (3x2 - 10) (x - 2)

    Step-by-step explanation:

    3x^2 - 16x + 20

    Step 1: Sum = - 16x

    Product = 60x^2

    Step 2: Find 2 numbers that their sum is - 16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and - 6

    Step 3: Replace - 16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20

    Step 4: Factorise the equation in step 3, like so;

    (3x^2 - 6x) ( - 10x + 20)

    3x (x - 2) - 10 (x - 2)

    (3x - 10) (x - 2)

    To check if the answer is correct, expand the bracket: (3x - 10) (x - 2)

    If the bracket is opened properly, you will get 3x^2 - 16x + 20
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Fully Factor 3x^2 - 16x + 20 A. (3x + 10) (x - 2) B. None of the answers are correct C. (3x - 10) (x - 2) D. (3x² - 4) (x - 5) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers