Which pair of complex factors results in a real number product? 15 (-15i) 3i (1 - 3i) (8 + 20i) (-8 - 20i) (4 + 7i) (4 - 7i)

Question

Mathematics

Easton Bennett

5 November, 00:27

Which pair of complex factors results in a real number product? 15 (-15i) 3i (1 - 3i) (8 + 20i) (-8 - 20i) (4 + 7i) (4 - 7i)

+5

Answers (2)

Know the Answer?

Stafford · Answer 1

D. (4+7i) (4-7i)

Maeve Kidd · Answer 2

(4 + 7i) (4 - 7i)

Step-by-step explanation:

This pair will produce a real answer because they are complex conjugates.

Complex conjugates (a+bi) (a-bi) when multiplied together form a real number (a^2 + b^2)