What is the equation of the line that is tangent to the circle of radius 8 at (0,-8) and whose center is at the origin? Click to select your answer 2 3 4

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Mathematics

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8 January, 19:16

What is the equation of the line that is tangent to the circle of radius 8 at (0,-8) and whose center is at the origin? Click to select your answer 2 3 4

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Stephany · Answer 1

y=-8

Step-by-step explanation:

So if you draw a circle with center at the origin (0,0) with radius 8.

So we have:

That means the radius stretches to (0,-8); down 8 units from (0,0).

The radius stretches to (0,8); up 8 units from (0,0).

The radius stretches to (8,0); right 8 units from (0,0).

The radius stretches to (-8,0); left 8 units from (0,0).

We are looking for a line tangent to our circle at (0,-8). Since this was down 8 units. Then our equation is horizontal and y=a number. They-coordinate in (0,-8) is - 8, so the we have y=-8.

If someone said tangent at (0,8), we would have said y=8.

If someone said tangent at (8,0), we would have said x=8.

If someone said tangent at (-8,0), we have have said x=-8.