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16 November, 15:28

What is the 32nd term of the arithmetic sequence where a1 = - 32 and a9 = - 120?

A) - 384

B) - 373

C) - 362

D) - 351

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Answers (2)
  1. 16 November, 17:03
    0
    (-120 - (-32)) / (9 - 1) = - 11

    a (n) = - 32 - 11 * (n - 1)

    a (32) = - 32 - 11 * (32 - 1) = - 373
  2. 16 November, 18:35
    0
    a = - 32

    tn9 = - 120

    L = a + (n - 1) * d

    -120 = - 32 + (9 - 1) * d Add 32 to both sides.

    -88 = 8*d Divide by 8

    -11 = d

    a_32 = - 32 + (32 - 1) * -11

    a_32 = - 32 + 31*-11

    a_32 = - 373
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