Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y=2x^2+4x-3

Step-by-step explanation:

write this expression : f (x) = a (x-h) ²+k

when the axis of symmetry is the line : x = h and the vertex A (h, k)

y=2x²+4x-3

y = 2 (x²+2x - 3/2)

y=2 ((x²+2x+1) - 1 - 3/2)

y = 2 ((x+1) ² - 5/2)

y = 2 (x+1) ² - 5 ... vertex form x = - 1 the axis of symmetry and A (-1,-5) the vertex

The equation of the axis of symmetry is x = - 1.

The coordinates of the vertex are (-1, - 5).

Step-by-step explanation:

y = 2x^2 + 4x - 3

y = 2 (x^2 + 2x) - 3

y = 2[ (x + 1) ^2 - 1] - 3

y = 2 (x + 1) ^2 - 5.

The equation of the axis of symmetry is x = - 1.

The coordinates of the vertex are (-1, - 5)