Find 3 consecutive odd integers such that the sum of the smallest number and the middle number is 27 less than 3 times the largest number

Let consecutive odd numbers be

x, x+2, x+4

Smallest number = x

Middle number = x+2

Largest number = x+4

According to condition (x) + (x+2) - 27 = 3 (x+4)

x+x+2-27 = 3 (x+4)

2x-25 = 3x+12

Subtracting 2x and 12 both sides

2x-25-2x-12=3x+12-2x-12

-37 = x this is smallest odd number.

Other two odd numbers are (x+2) = (-37+2) = (-35)

& (x+4) = (-37+4) = (-33)

so three consecutive odd numbers are - 37,-35, - 33