Vertex of y=2x^2-16x+8

First you use the formula (-b/2a) to find the axis of symmetry (or the x value) and then you plug that into the equation to find the y value.

a = 2

b = - 16

16/2 (2) = 16/4=4

(4, x) so we have the x-value and now we plug 4 into the original equation

y=2 (4) ^2-16 (4) + 8

y=2 (16) - 64+8

y=32-64+8

y=-24

So the vertex is at (4,-24)