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Yesterday, 21:41

Given the function f (x) = 3^x, find the value of f^-1 (27)

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  1. Today, 00:53
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    This is asking you to solve the equation ...

    ... 27 = 3^x

    You can use logarithms to find

    ... log (27) = x·log (3)

    ... log (27) / log (3) = x = 1.43136376 ... / 0.47712125 ...

    ... x = 3

    Or, you can use your knowledge of small cubes and match exponents.

    ... 3^3 = 3^x

    ... 3 = x
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