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29 May, 07:47

For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be considered independent of the other days. What is the probability that Sasha's first delay due to traffic will occur after the fifth day of travel to work?

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  1. 29 May, 08:54
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    0.3277 = 32.77%

    Step-by-step explanation:

    If we want the probability for Sasha being late after the fifth day, we need that in the first five days she is not late, which has a probability of 1 - 0.2 = 0.8

    So, multiplying the probability for each day, we have that:

    P = 0.8 * 0.8 * 0.8 * 0.8 * 0.8 = 0.3277 = 32.77%

    So we have a probability of 32.77% that Sasha's first delay will occur after the fifth day.
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