Ask Question
30 August, 19:52

If h (x) = 3x - 1 and j (x) = - 2x, solve h[j (2) ] and select the correct answer below.

+1
Answers (2)
  1. 30 August, 20:09
    0
    h[j (2) ] = - 13.

    Step-by-step explanation:

    Given : If h (x) = 3x - 1 and j (x) = - 2x,

    To find : solve h[j (2) ].

    Solution : We have given

    h (x) = 3x - 1 and j (x) = - 2x

    For x = 2,

    j (2) = - 2 (2).

    j (2) = - 4.

    h[j (2) ] = h (-4).

    h (4) = 3 (-4) - 1.

    h (4) = - 12 - 1.

    h[j (2) ] = h (4) = - 13.

    h[j (2) ] = - 13.

    Therefore, h[j (2) ] = - 13.
  2. 30 August, 23:41
    0
    h[j (2) ] = -13

    Step-by-step explanation:

    The first step is to solve j (2) by putting x=2 into j (x)

    j (2) = - 2 (2) = - 4

    Now we put x = - 4 into h (x)

    h (-4) = 3 (-4) - 1

    h (-4) = - 12-1 = - 13

    h[j (2) ] = -13
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If h (x) = 3x - 1 and j (x) = - 2x, solve h[j (2) ] and select the correct answer below. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers