colby and jaquan are growing bacteria in an experiment in a labatory. colby starts with 50 bacteria and the number of bacteria doubles every 2 hours. jaquan has a different typee of bacteria that doubles every 3 hours how many bacteria should jaquuan start with so that they have the same amount at the end of the day

Question

Mathematics

Jerome Rowland

1 May, 08:10

colby and jaquan are growing bacteria in an experiment in a labatory. colby starts with 50 bacteria and the number of bacteria doubles every 2 hours. jaquan has a different typee of bacteria that doubles every 3 hours how many bacteria should jaquuan start with so that they have the same amount at the end of the day

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Alexzander Combs · Answer 1

Answer:400

Step-by-step explanation:

3 hours: 400 times 2=800

6 hours: 800 times 2=1600

9 hours: 1600 times 2=3200

12 hours: 3200 times 2=6400

15 hours: 6400 times 2 = 12800

18 hours: 12800 times 2=25,600

21 hours: 25,600 times 2 = 51200

24 hours: 102,400