What is 2 (log3 (8) + log3 (z)) - log3 (3^4 - 7^2) written as a simple logarithm?

the answer is

B on edge

log₃ (2z²)

Step-by-step explanation:

2 (log₃8 + log₃z) - log₃ (3⁴ - 7²)

= 2[log₃ (2³) + log₃z] - log₃ (81 - 49)

= 2 (3log₃2 + log₃z) - log₃ (32)

= 6log₃2 + 2log₃z - log₃ (2⁵)

= 6log₃2 + 2log₃z - 5log₃2

= log₃2 + log₃ (z²)

= log₃ (2z²)